The equation of line AB is y = 2x + 4. Write an equation of a line parallel to line AB in slope-intercept form that contains point (3, −2). (4 points) y = 2x + 4 y = negative 1 over 2 x − 1 over 2 y = − 1 over 2 x − 7 over 2 y = 2x − 8

ANSWER[tex]y = 2x - 8[/tex]EXPLANATION To find the equation of a straight line, we need the slope and a point on that line.We were given the equation of another line that will help us determine the slope . The given line has equation:[tex]y = 2x + 4[/tex]This equation is of the form[tex]y = mx + b[/tex]where [tex]m = 2 \: \: is \: the \: \: slope.[/tex]Since our line of interest is parallel to this line, their slopes are the same.The line also contains the point (3,-2).So we substitute the slope and point into the slope-intercept formula:[tex] - 2= 2(3)+ b[/tex][tex] - 2 =6 + b[/tex][tex] \implies \: b = - 2 - 6 = - 8[/tex]The required equation is[tex]y = 2x - 8[/tex]