MATH SOLVE

4 months ago

Q:
# What is the equation in point slope form of the line that passes through the point (1, −2) and has a slope of 3?A. y−1=3(x+2)B. y−2=3(x+1)C. y+1=3(x−2)D. y+2=3(x−1)

Accepted Solution

A:

All we have to do is get y alone and input our values to see if it makes the statement true.

y - 1 = 3(x + 2)

Add 1 to both sides.

y = 3x + 7

y = 3(1) + 7

y = 3 + 7

y = 10

FALSE

y - 2 = 3(x + 1)

Add 2 to both sides.

y = 3x + 3

y = 3(1) + 3

y = 3 + 3

y = 6

FALSE

y + 1 = 3(x - 2)

Subtract 1 from both sides.

y = 3x - 7

y = 3(1) - 7

y = 3 - 7

y = -4

FALSE

y + 2 = 3(x - 1)

Subtract 2 from both sides.

y = 3x -5

y = 3(1) - 5

y = 3 - 5

y = -2

TRUE

The only equation that makes this statement true is D, y + 2 = 3(x - 1).

y - 1 = 3(x + 2)

Add 1 to both sides.

y = 3x + 7

y = 3(1) + 7

y = 3 + 7

y = 10

FALSE

y - 2 = 3(x + 1)

Add 2 to both sides.

y = 3x + 3

y = 3(1) + 3

y = 3 + 3

y = 6

FALSE

y + 1 = 3(x - 2)

Subtract 1 from both sides.

y = 3x - 7

y = 3(1) - 7

y = 3 - 7

y = -4

FALSE

y + 2 = 3(x - 1)

Subtract 2 from both sides.

y = 3x -5

y = 3(1) - 5

y = 3 - 5

y = -2

TRUE

The only equation that makes this statement true is D, y + 2 = 3(x - 1).